Вопрос \(5119c\)

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Позволять \[3^x=7^y=63^z=k\] Так \[3=k^(1/x)\] \[7=k^(1/y)\] а также \[63=k^(1/z)\] \[=>3^2xx7=k^(1/z)\] \[=>(k^(1/x))^2xxk^(1/y)=k^(1/z)\] \[=>k^(2/x)xxk^(1/y)=k^(1/z)\] \[=>k^(2/x+1/y)=k^(1/z)\] \[=>2/x+1/y)=1/z\] \[=>(2y+x)/(xy)=1/z\] \[=>z(2y+x)=xy\]

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